EXERCISE UN ENGLISH PART 2 LESSON BY : ENDRA ARI PRABAWA (07301244071)

THE NATURAL OF LOGARITHM

g logarithm of a equals x, it is mean that g to the power of x equals a. g logarithm b equals y, it is mean that g to the power of y equals b.

if,

g logarithm a equals x, it is mean that g to the power of x. g logarithm b equals y, it is mean that b equals g to the power of y. So we can conclude that :

• a cross b equals g to the power of x cross g to the power of y. it is mean that a cross b equals g to the power of x plus y in bracket.

• g logarithm a cross b in bracket equals g logarithm g to the power of open bracket x plus y close bracket, it is equals to : open bracket x plus y close bracket cross g logarithm g. we know that g logarithm of g is 1, so we can conclude that g logarithm open bracket a cross b close bracket equals x pus y. And then, we can write : g logarithm open bracket a cross b close bracket equals g logarithm a plus g logarithm b.

• a devided by b equals g to the power of x devided by g to the power if y, it is same as a devided by b equals g to the power of x minus y in bracket. It is same as g logarithm a devided by b in bracket equals g logarithm g to the power of x minus y in bracket . it is same as g logarithm a devided by b in bracket equals g logarithm a minus g logarithm b.

• g logarithm a to the power of n equals g logarithm open bracket a cross a cross a till n factor of a close bracket. So it is mean that “g logarithm a to the power of n equals g logarithm a plus g logarithm a plus g logarithm a plus … till n factor of a…” so, we can conclude that “g logarithm a to the power of n equals n cross g logarithm a.”

TO FIND OUT THE VALUE OF PHI NUMBER.

We can follow the value of phi, by the ratio of area of circle to its distance square and ratio circle the circle with its diameter is constant. The value of phi number got from measurement of area of circle that is open bracket 8 over 9 times d close bracket to the power of 2; by d is diameter, and d equals 2 times r; by r is radius. And got by equation of area of circle (A) equals open bracket 8 devided by 9 times 2 times r close bracket to the power of 2, equivalent A equals 64 over 81 times 4 times r to the power of 2, equivalent A equals 256 over 81 times r to the power of 2, equivalent 3,16 times r to the power of 2. Considering formula look for the area of circle equals phi times r to the power of 2, so, value of phi is 3,14